2x^2-16+32=5

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Solution for 2x^2-16+32=5 equation: 



2x^2-16+32=5

We move all terms to the left:

2x^2-16+32-(5)=0

We add all the numbers together, and all the variables

2x^2+11=0

a = 2; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·2·11
Δ = -88
Delta is less than zero, so there is no solution for the equation

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